Non-zero solution of a homogenous system

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SUMMARY

The theorem states that the homogeneous system Ax=0 has a non-trivial solution if and only if the determinant of matrix A, denoted as det(A), equals zero. This relationship is established through the geometric interpretation of the determinant, which represents the signed volume change of a linear transformation. When det(A)=0, the transformation collapses the volume element into a lower-dimensional subspace, indicating that the basis vectors are not linearly independent, thus confirming the existence of a non-trivial solution.

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sunny110
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Hi,
Could anyone give me a proof for the following theorem?
Theorem : Ax=0 has a non-trivial solution iff det(A)=0

Thanks in advance.
/Sunny
 
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You will find the proof in books such as "Linear Algebra" by Lang. I suggest you check out that book.
 
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This is easier to understand if you think about the geometric meaning of a determinant.

A matrix [itex]A[/itex] represents a linear transformation in a given basis. The determinant is a property of the matrix, but it's also a property of the linear transformation it represents, independently of any basis. The determinant is simply the signed volume change of the volume element.

Now we can see what a zero determinant means: it means the transformed volume element is zero. This transformation has squished it down into a lower-dimensional subspace, which means the mapped basis vectors can't be linearly independent. That means there's a nontrivial linear combination of basis vectors which maps to 0. In other words, there must be some [itex]x[/itex] in this basis such that [itex]Ax = 0[/itex].
 
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