Nonhomogeneous 2nd order dif equation

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SUMMARY

The discussion focuses on solving a nonhomogeneous second-order differential equation represented by xy'' - 2y' = -2/x² with initial conditions y(1) = -1/3 and y'(1) = 1. The user seeks assistance specifically using the method of constant variation, which they are familiar with, but also expresses openness to alternative methods. A suggested approach involves transforming the equation into a first-order ordinary differential equation (ODE) for u = y', leading to the equation u' - 2/x * u = -2/x³, which can be solved using an integrating factor.

PREREQUISITES
  • Understanding of second-order differential equations
  • Familiarity with the method of constant variation
  • Knowledge of integrating factors in first-order ODEs
  • Basic skills in variable substitution techniques
NEXT STEPS
  • Study the method of constant variation in detail
  • Learn how to apply integrating factors to first-order ODEs
  • Explore variable substitution techniques for differential equations
  • Practice solving nonhomogeneous differential equations with various methods
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Students and professionals in mathematics, particularly those studying differential equations, as well as educators looking for effective teaching methods for solving nonhomogeneous second-order differential equations.

darjiaus7
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Hello guys . I want to do nonhomogeneous 2nd order dif equation..I am trying to do this for 2 days , but I can't get good answer. Can you show me how to do this equation with constant variation method ( i know it best) or other I would be very gratefull , because after 2 days of trying I am surrendered... xy''-2y' = -\frac{2}{x^2} ; y(1)=-\frac{1}{3} ; y'(1)=1
 
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darjiaus7 said:
Hello guys . I want to do nonhomogeneous 2nd order dif equation..I am trying to do this for 2 days , but I can't get good answer. Can you show me how to do this equation with constant variation method ( i know it best) or other I would be very gratefull , because after 2 days of trying I am surrendered... xy''-2y' = -\frac{2}{x^2} ; y(1)=-\frac{1}{3} ; y'(1)=1

This is a first-order ODE for u = y&#039;: <br /> u&#039; -\frac{2}{x}u = -\frac{2}{x^3}. It has an integrating factor.
 
change variables
##\mathrm{u}(x)=x^{-2} \mathrm{y}^\prime (x)##
 

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