2nd-order nonhomogeneous equation

  • Thread starter Thread starter yecko
  • Start date Start date
  • Tags Tags
    Nonhomogeneous
Click For Summary

Homework Help Overview

The discussion revolves around a second-order nonhomogeneous differential equation. Participants are exploring the appropriate form of the particular solution, particularly in relation to the presence of terms involving \( e^{2t} \) and polynomial factors.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to determine the correct form of the particular solution, questioning why certain terms cannot be included. There are discussions about the derivatives of the proposed solutions and how they affect the overall equation.

Discussion Status

Some participants have provided insights into the differentiation process and the implications for the form of the particular solution. There is an ongoing exploration of the correct approach to take, with no clear consensus yet on the final form of the solution.

Contextual Notes

There are mentions of constraints regarding the use of certain terms in the particular solution due to the nature of the nonhomogeneous equation. Participants are also encouraged to present their problems clearly without relying on images.

yecko
Gold Member
Messages
275
Reaction score
15

Homework Statement


螢幕快照 2018-03-10 上午11.05.39.png


Homework Equations


2nd order nonhomogeneous equation

The Attempt at a Solution


(answers typed in in the pic)
for part c, if I can't put Ate^(2t) & Be^(2t), how is the form of particular equation like?
I have used Y=(At+B)e^(2t)+(Ct+D), because of the largest power of the equation.
Thank you.
 

Attachments

  • 螢幕快照 2018-03-10 上午11.05.39.png
    螢幕快照 2018-03-10 上午11.05.39.png
    34.8 KB · Views: 1,671
Physics news on Phys.org
The derivative of Be^(2t) should be 2Be^(2t),
Then you should have this for y':
Ae^(2t) + 2Ate^(2t) + 2Be^(2t) + C

Then your y'' will change as it is the derivative of y'.
 
yecko said:

Homework Statement


View attachment 221738

Homework Equations


2nd order nonhomogeneous equation

The Attempt at a Solution


(answers typed in in the pic)
for part c, if I can't put Ate^(2t) & Be^(2t), how is the form of particular equation like?
I have used Y=(At+B)e^(2t)+(Ct+D), because of the largest power of the equation.
Thank you.

Do NOT post pictures of problems/equations. Your images are unreadable on my screen, and I suspect that almost all helpers will be willing to assist you. Just type out the main parts of the problem---you don't need to type everything, just the most important parts. After all, if you want us to volunteer out time freely you can at least make the effort to present your problem clearly.
 
scottdave said:
The derivative of Be^(2t) should be 2Be^(2t),
Then you should have this for y':
Ae^(2t) + 2Ate^(2t) + 2Be^(2t) + C

Then your y'' will change as it is the derivative of y'.
other than my fault in deriving Y', my Y answer is also wrong
for Y, the comment is mentioned that the answer is without Ate^(2t) or Be^(2t), how can a particular equation without this two variables? thanks
 
Ray Vickson said:
Do NOT post pictures of problems/equations. Your images are unreadable on my screen, and I suspect that almost all helpers will be willing to assist you. Just type out the main parts of the problem---you don't need to type everything, just the most important parts. After all, if you want us to volunteer out time freely you can at least make the effort to present your problem clearly.
question:

In this problem you will use undetermined coefficients to solve the nonhomogeneous equation y''-4y'+4y=18te^(2t)-2e^(2t)-(4t+4)
with initial values y(0)=-3 and y'(0)=-6
Write the form of the particular solution and its derivatives. (Use A, B, C, etc. for undetermined coefficients. Y=?, Y'=?, Y''=?

sorry for not typing out in advance, because the screenshot gave the questions, my attempts, and comments which I thought it would be more comprehensive.
 
yecko said:
other than my fault in deriving Y', my Y answer is also wrong
for Y, the comment is mentioned that the answer is without Ate^(2t) or Be^(2t), how can a particular equation without this two variables? thanks
ok, finally i made it A+Bt+Ce^(2t)t^2+De^(2t)t^3 which is correct... why and when should I multiply t/t^2 to the particular equation? thanks
 
yecko said:
ok, finally i made it A+Bt+Ce^(2t)t^2+De^(2t)t^3 which is correct... why and when should I multiply t/t^2 to the particular equation? thanks

Because it works! There is no better reason than that.

A hundred years ago some smart people figured out that we should do such things, and all we need to do is take their advice. Basically, that is what education is all about.

You might well ask how these things were discovered in the first place. The answer, I am afraid, is that people try many different methods; some of them fail and are a waste of time, while others work. What you see in print are only the results of the successes, not the hours of wasted time and mountains of scrap paper that went into the exploration.
 
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
2
Views
2K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K