- #1

- 14

- 0

How do u go about doing this question?

x - 2y +z =4

y- z =3

(a^2 - a - 2)z = a+1

Determine values of a for which the system has no solution, one solution and many solutions

Stephen

- Thread starter salistoun
- Start date

- #1

- 14

- 0

How do u go about doing this question?

x - 2y +z =4

y- z =3

(a^2 - a - 2)z = a+1

Determine values of a for which the system has no solution, one solution and many solutions

Stephen

- #2

chiro

Science Advisor

- 4,790

- 132

Hey Stephen and welcome to the forums.

How do u go about doing this question?

x - 2y +z =4

y- z =3

(a^2 - a - 2)z = a+1

Determine values of a for which the system has no solution, one solution and many solutions

Stephen

You should for this problem set up an augmented system and apply row-operations.

You could use MATLAB though and invert the matrix in terms an unknown number a and then check that you don't get an inconsistent system since a is in the RHS vector.

Show us what augmented system have and row operations to get your reduced system

- #3

AlephZero

Science Advisor

Homework Helper

- 6,994

- 291

- Last Post

- Replies
- 2

- Views
- 2K

- Replies
- 5

- Views
- 578