Nonlinear Equation: Solve x,y,z

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SUMMARY

The discussion focuses on solving the nonlinear equation system defined by the relationships \(\frac{y+z}{a} = \frac{x+z}{b} = \frac{x+y}{c} = xyz\), where \(a\), \(b\), and \(c\) are non-zero constants. Participants explored various approaches to derive solutions for \(x\), \(y\), and \(z\), ultimately identifying the trivial solution (0,0,0) and suggesting a method to rewrite the equations for further analysis. The recommended approach involves substituting variables \(p\), \(q\), and \(r\) to simplify the equations and derive non-zero solutions.

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  • Familiarity with algebraic manipulation and substitution techniques
  • Knowledge of mathematical notation and symbols
  • Basic experience with solving equations involving multiple variables
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  • Study systems of equations and their solution techniques
  • Explore the concept of trivial vs. non-trivial solutions in mathematical contexts
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dirk_mec1
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Homework Statement


Solve x,y and z from <br /> \frac{y+z}{a}= \frac{x+z}{b}=\frac{x+y}{c} = xyz<br />

wit a,b,c not equal to zero.

Homework Equations


The Attempt at a Solution


I have no idea how to start. I've tried several things but it seems like I'm missing something. I did find the trivial solution (0,0,0).
 
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dirk_mec1 said:

Homework Statement


Solve x,y and z from <br /> \frac{y+z}{a}= \frac{x+z}{b}=\frac{x+y}{c} = xyz<br />

wit a,b,c not equal to zero.

Homework Equations





The Attempt at a Solution


I have no idea how to start. I've tried several things but it seems like I'm missing something. I did find the trivial solution (0,0,0).

You say you tried several things. What were they? You need to show your work.
 
dirk_mec1 said:

Homework Statement


Solve x,y and z from <br /> \frac{y+z}{a}= \frac{x+z}{b}=\frac{x+y}{c} = xyz<br />

wit a,b,c not equal to zero.

Homework Equations


The Attempt at a Solution


I have no idea how to start. I've tried several things but it seems like I'm missing something. I did find the trivial solution (0,0,0).

Rewrite the equation as
$$\frac{1}{a}\left(\frac{1}{xz}+\frac{1}{xy}\right)=\frac{1}{b} \left( \frac{1}{yz}+\frac{1}{xy}\right)=\frac{1}{c}\left(\frac{1}{yz}+\frac{1}{xz}\right)=1$$
Substitute ##1/(xy)=p, 1/(yz)=q## and ##1/(xz)=r##. Form three equations to find p, q and r. This gives the possible non-zero solutions.
 
Understood, thanks.
 

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