Nonlinear System Solution Strategies

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SUMMARY

The discussion focuses on solving the nonlinear system defined by the equations x² - 2y² = 16 and x² + y² = 25. Participants highlighted the importance of correctly subtracting both sides of the equations to avoid confusion, particularly emphasizing the need to account for the right-hand side (RHS) during calculations. A participant initially miscalculated y², leading to confusion, but ultimately clarified the solution process with community assistance. The correct approach involves careful manipulation of both sides of the equations to derive valid solutions.

PREREQUISITES
  • Understanding of nonlinear equations
  • Familiarity with algebraic manipulation
  • Knowledge of quadratic equations
  • Ability to interpret mathematical notation
NEXT STEPS
  • Study methods for solving nonlinear systems of equations
  • Learn about algebraic techniques for manipulating equations
  • Explore the use of graphical methods to visualize solutions
  • Investigate the implications of complex numbers in solutions
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Students studying algebra, mathematics educators, and anyone interested in solving nonlinear systems of equations.

oray
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Homework Statement



Solve the nonlinear system.

x^2-2y^2=16
x^2+y^2=25

Homework Equations



n/a?

The Attempt at a Solution



ive tried subtracting 1 equation from the other...
(x^2-2y^2+9)=25
-(x^2+y^2)=25
-3y^2+9=25
-3y^2=16
y^2=-16/3
y=root of -16/3...
im not even sure if that part is right, also, i don't know where to go after that.
help?
 
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You've forgotten to subtract the RHS as well.
 
huh? I am confused? what is the RHS? i really am confused on where to start in general.
 
Last edited:
oray said:
huh? I am confused? what is the RHS? i really am confused on where to start in general.

When you subtracted one equation from the other, you subtracted the left-hand side (LHS) of your equations, but did not do the same for the right-hand side (RHS), which was 25-25 = 0.
 
okay...
(x^2-2y^2+9)=25
-(x^2+y^2)=25
-3y^2+9=0
-3y^2=-9
y^2=-3
y=null?
 
You have -3y^2=(-9). That doesn't give you y^2=(-3), does it? I think I remember once dividing -9 by -3 and I didn't get -3.
 
awesome. figured it out. thanks for all the help people :)
 

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