Normal derivative in spheroidal coordinate

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SUMMARY

The discussion focuses on calculating the normal derivative to the surface of an oblate spheroid using spheroidal coordinates. The relationship between spheroidal coordinates and Cartesian coordinates is defined by the equations: x=a√((1+u²)(1-v²))cos(φ), y=a√((1+u²)(1-v²))sin(φ), and z=a u v. To find the normal derivative, participants recommend calculating a basis for the tangent space and then taking the cross product of the tangent vectors.

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  • Understanding of oblate spheroids and spheroidal coordinates
  • Familiarity with Cartesian coordinate transformations
  • Knowledge of vector calculus, specifically tangent spaces and cross products
  • Basic proficiency in differential geometry concepts
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  • Study the mathematical properties of oblate spheroids and their applications
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  • Explore vector calculus techniques for calculating cross products
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dexturelab
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Hi PhysicsForums,
I am calculating something related to the spheroidal membrane and want to ask you a question.

I consider a oblate spheroid (Oblate spheroidal coordinates can also be considered as a limiting case of ellipsoidal coordinates in which the two largest semi-axes are equal in length.)

In spheroidal coordinate, the relationship to Cartesian coordinates is
x=a\sqrt((1+u^2) (1-v^2))\cos(\phi)
y=a\sqrt((1+u^2) (1-v^2))\sin(\phi)
z=a u v

Now, I want to know how to achieve the normal derivative to the surface of a spheroid, in terms of the derivatives of u, v and \phi.

Thank you very much.
 
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Just calculate a basis of the tangent space and take the cross product.
 

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