Normal force during a push up problem

[Max238]

A person whose weight is W = 633 N doing push-ups.

l=====x====l==0
______ _____
0.885 0.358


Assume L1 = 0.885 m and L2 = 0.358 m. Calculate the normal force exerted by the floor on each hand, assuming that the person holds this position.

My work so far:
thinking L1 + L2 = 633
and .358Rhands=.885Rfeet; Rhands and Rfeet x and y respectivelyl

with a little substitution .358(633-x)=.885x
What I am having trouble is the simple math of solving this. I'm either doing something illogical or can't do simple math.
If this is wrong please tell me, if not what do I do? Maybe I've just been working on this problem a little too long...

 

[mbrmbrg]

I don't understand the diagram. Are the two positions those of his right and left hands or those of his hands and his feet?

 

[Max238]

they are the hands and feet
you are seeing a sideview of the person with the x being his center of gravity
sorry