- #1

Max238

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l=====x====l==0

______ _____

0.885 0.358

Assume L1 = 0.885 m and L2 = 0.358 m. Calculate the normal force exerted by the floor on each hand, assuming that the person holds this position.

My work so far:

thinking L1 + L2 = 633

and .358Rhands=.885Rfeet; Rhands and Rfeet x and y respectivelyl

with a little substitution .358(633-x)=.885x

What I am having trouble is the simple math of solving this. I'm either doing something illogical or can't do simple math.

If this is wrong please tell me, if not what do I do? Maybe I've just been working on this problem a little too long...