- #1
Hypnos_16
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Homework Statement
A car moving at 13.5 m/s encounters a bump that has a circular cross-section with a radius of 56.8 m. What is the normal force exerted by the seat of the car on a 70.8 kg passenger when the car is at the top of the bump?
v = 13.5
r = 56.8
m = 70.8kg
Homework Equations
So i know the forces acting on a object on the inside of a Loop, i know it being on the outside and hitting a bump is a factor but to me it seems like it should just be
Fn = m(v^2 / r) + mg
The Attempt at a Solution
in using that formula I've come up with
Fn = m(v^2 / r) + mg
Fn = 70.8(13.5^2 / 56.8) + (70.8 x 9.81)
Fn = 70.8(3.21) + 695
Fn = 227 + 695
Fn = 922N
but that's not the right answer,
can someone help me out?