Normal force on a 3.80 kg block in equilibrium on a 38.4° incline

[KB94]

Homework Statement

A 3.80 kg block is in equilibrium on an incline
of 38.4◦.
The acceleration of gravity is 9.81 m/s2 .
What is Fn of the incline on the block?
Answer in units of N.

Homework Equations

The Attempt at a Solution

FgsinΘ=mgsinΘ=3.8*9.81*sin38.4°=24.04
FgcosΘ=mgcosΘ=3.8*9.81*cos38.4°=28.49

This is from an online assignment. The second equation should've given me the correct value, but when I input the answer, the system tells me it's incorrect. Could anyone enlighten me on this situation? Maybe I'm doing something wrong. Please I would appreciate a quick reply. Thank you.

 

[ideasrule]

I get 29.21.

 

[KB94]

Oh hehe I must've made a mistake while calculating. Thank you very much. It's correct.

 

[berkeman]

FgsinΘ=mgsinΘ=3.8*9.81*sin38.4°=24.04
FgcosΘ=mgcosΘ=3.8*9.81*cos38.4°=28.49

I get the same as ideasrule. You have both of your answers off, so there must be something wrong with the way you are typing them into the calculator.

Also, I'm not sure what you mean by FgcosΘ=mgcosΘ. What is Fg? You should probably write it as:

F=mgcosΘ