Normal Forces on a Ferris Wheel: Is the Top or Bottom Greater?

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SUMMARY

The discussion centers on the analysis of normal forces experienced by a Ferris wheel rider at the top and bottom of the circular path. Using Newton's 2nd Law and centripetal acceleration, it is established that the normal force exerted by the seat on the rider is greater at the bottom of the Ferris wheel compared to the top. The equations derived from free body diagrams confirm that at the top, the normal force (Fn) is counteracted by gravitational force (mg) and centripetal acceleration, while at the bottom, the normal force must overcome gravitational force to provide the necessary centripetal force.

PREREQUISITES
  • Understanding of Newton's 2nd Law
  • Knowledge of centripetal acceleration
  • Ability to draw and interpret free body diagrams
  • Familiarity with forces acting on objects in circular motion
NEXT STEPS
  • Study the relationship between centripetal force and normal force in circular motion
  • Learn how to calculate centripetal acceleration in different scenarios
  • Explore the effects of varying speeds on normal forces in circular motion
  • Investigate real-world applications of forces in amusement park rides
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of forces acting on objects in circular motion, particularly in the context of amusement park rides like Ferris wheels.

Dannystu
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Homework Statement


A Ferris wheel rider moves in a vertical circle of radius r at constant speed v. Therefore, he experiences a centripetal acceleration a.

Homework Equations


Is the normal force that the seat exerts on the rider at the top of the circle less than, more than, or the same as the normal force the the bottom of the ride?

Is the normal force equal to the weight?

Explain your answers using Newton's 2nd Law with centripetal acceleration.

Thank you!
 
Last edited:
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What are your thoughts on the question? Try drawing a free body diagram of the rider at both the top and bottom of the circle.
 
I drew my free body diagram- when the rider is on top, I have the normal force pointing up and weight and acceleration pointing down towards the center of the wheel.

When the rider is at the bottom, the normal force and acceleration are pointing up and the weight is pointing down.

For top-
F=m*a
-Fn+mg=m*a

For bottom-
F=m*a
Fn-mg=m*a

Is this right so far?
 
Last edited:
So the normal force is greater at the bottom? Correct? Thanks!
 

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