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Normal of a direction vector

  1. Oct 21, 2009 #1
    How may I solve for the normal of a direction vector?

    If, for example, the direction vector is (1,2,-2), then what is its normal.
    Last edited: Oct 21, 2009
  2. jcsd
  3. Oct 22, 2009 #2
    Any normal vector (x, y, z) satisfies (x, y, z).(1, 2, -2) = 0, so you just have to solve the linear equation x + 2y - 2z = 0.
  4. Oct 22, 2009 #3


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    The plane x+2y- 2z= 0 is normal to that given vector. Any vector in that plane will be normal to the vector.
  5. Oct 22, 2009 #4
    Ok. Got it, thanks.
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