Normalizaed wave function of the hydrogen atom

Click For Summary
SUMMARY

The normalized wave functions of the hydrogen atom for the quantum numbers n=1, l=0, and ml=0 are derived from the solutions to the Schrödinger equation. Specifically, this involves solving the individual differential equations for the radial function R(r), the polar angle function Θ(θ), and the azimuthal angle function Φ(φ). For the case of n=1, l=0, and ml=0, both Θ(θ) and Φ(φ) are constant, simplifying the differential equations significantly. The process requires substituting the quantum numbers into the equations and solving them accordingly.

PREREQUISITES
  • Understanding of the Schrödinger equation
  • Familiarity with ordinary differential equations
  • Knowledge of quantum mechanics terminology
  • Basic concepts of quantum numbers (n, l, ml)
NEXT STEPS
  • Study the solutions to the Schrödinger equation for the hydrogen atom
  • Learn about the separation of variables technique in differential equations
  • Explore the significance of quantum numbers in quantum mechanics
  • Investigate the mathematical properties of spherical harmonics
USEFUL FOR

Students of quantum mechanics, physicists, and anyone interested in understanding the mathematical foundations of atomic structure and wave functions.

asdf1
Messages
734
Reaction score
0
how do you find the normalized wave functions of the hydrogen atom for n=1, l=0 and ml=0?
in my textbook, it's a table, but i have no idea where the figures come from...
 
Physics news on Phys.org
asdf1 said:
how do you find the normalized wave functions of the hydrogen atom for n=1, l=0 and ml=0?
in my textbook, it's a table, but i have no idea where the figures come from...

You do it by finding the solution for the Schrödinger equation for the hydrogen atom. This means finding the solutions of the individual differential equations for the functions R(r), \Theta(\theta) and \Phi(\phi).

Many introductory textbooks work through the solution for \Phi(\phi) because its equation is rather easy. But I didn't see the complete solution for \Theta(\theta) and \Phi(\phi) until my graduate school QM courses. They're that messy!

Oh wait, I was thinking of the general solution for any n, l, m. You want specifically n=1, l=0, m=0. That case might not be too bad, after you substiute those values of n, l, m into the individual differential equations for the three variables. \Theta(\theta) and \Phi(\phi) both turn out to be constant in this case, so their differential equations must be very simple! :smile:
 
Last edited:
\Theta(\theta)
but the original function isn't known, right? so how do you solve it?
 
That's what the Schrödinger equation is for, or rather the individual ordinary differential equations that you get after you separate the S.E.

Solving an algebraic equation like x^2 - 5x + 6 = 0 gives you a number for x, or a set of numbers. Solving a differential equation like d^2 \Phi(\phi) / d \phi^2 = -m_l^2 \Phi(\phi) gives you a function for \Phi(\phi), or a set of functions.
 
thank you very much! :)
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
2K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
29
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K