Normalize the wave function and more Please help

Click For Summary

Homework Help Overview

The discussion revolves around normalizing a wave function and calculating expectation values in quantum mechanics. The original poster presents a wave function and seeks assistance with normalization, expectation values of position and position squared, and the implications of a parameter being negative.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the normalization process and the integration of the wave function, with some questioning the correctness of the original poster's calculations. There are inquiries about the expectation values and the physical implications of parameters in the wave function.

Discussion Status

Several participants have provided feedback on the normalization and integration steps, suggesting corrections and alternative approaches. The original poster has attempted to revise their calculations based on this feedback, indicating progress in their understanding, though they still express confusion regarding the integration process.

Contextual Notes

There is mention of difficulties with integrating absolute values and the implications of a parameter being negative, which raises questions about the physical validity of the wave function in that case.

s_gunn
Messages
33
Reaction score
0
normalize the wave function and more! Please help!

Homework Statement



i) Normalize the wave function

ii) Calculate <x>

iii) Calculate [tex]<x^{2}>[/tex]

iv) What would happen if a < 0?



Homework Equations



[tex]\psi\left(x\right) = N\left(1+i\right)exp\left(-a|x|\right)[/tex], for -inf < x < inf and a > 0

The Attempt at a Solution



It would take ages for me to work out the latex for all my steps (I'm new to latex!) so I'll do what i need to and hope someone can help!

First:

[tex]^{inf}_{-inf}\int 2N^{2}e^{-2a|x|}dx[/tex]
[tex]=N^{2}\left[-e^{-2a|x|}\right]^{inf}_{-inf}[/tex]

so: [tex]\frac{-N^{2}}{a}=1[/tex]
so: [tex]N=\sqrt{\frac{-1}{a}}[/tex]

therefore:
[tex]\psi\left(x\right) = \sqrt{\frac{-1}{a}}\left(1+i\right)exp\left(-a|x|\right)[/tex]


ii+iii) for the expectation values, I got both equalling zero

iv) and if a < 0, you'd get exponential growth as x approaches infinity (+ and -)

Is this right??!

I get so confused when the limits are infinity!
 
Physics news on Phys.org


I think you lost a 2 when doing your initial normalization.

You should get an expectation value for position of zero. Think about physically why that is the case.

The expectation value of x^2 should not be zero. Check that integral.

Your completely correct on the a<0 regieme. The function would increase to infinity as x goes to infinity and you could not normalize the function. The solution becomes non-physical.
 


Your integration to normalize the WF looks wrong. You shouldn't get a negative answer when you're integrating a positive definite function. I'd try it again more carefully if I were you.
 


Also, it is difficult to integrate an absolute value. You need to split the integral into two regions. One where the Abs(x) = x and one where Abs(x) = -x
 


Ok! I redid the integration for the wave function and got [tex]N=\sqrt{\frac{a}{2}}[/tex] now, which looks a lot better and my expectation value of x is still zero so that's good too! My problem now is that when i try to calculate the expectation value of x^2, (using integration by parts) I just keep getting deeper and deeper into it!

[tex]<x^{2}>=^{inf}_{-inf}\int\psi^{*}x^{2}\psi\: dx[/tex]
[tex]=\sqrt{\frac{a}{2}}\left(1-i\right)e^{-a|x|}x^{2}\sqrt{\frac{a}{2}}\left(1-i\right)e^{-a|x|}\: dx[/tex]
[tex]=^{inf}_{-inf}\int ax^{2}e^{-2a|x|}[/tex]
[tex]=^{0}_{-inf}\int ax^{2}e^{2ax}+\;^{inf}_{0}\int ax^{2}e^{-2ax}[/tex]
[tex]=\left[\frac{x^{2}e^{2ax}}{2}\right]^{0}_{-inf}-\:^{0}_{-inf}\int \frac{e^{2ax}}{x}\:dx+\left[\frac{-x^{2}e^{-2ax}}{2}\right]^{inf}_{0}-\:^{inf}_{0}\int \frac{-e^{-2ax}}{x}\:dx[/tex]

=...

so far I have carried on another 2 integrals and the denominator in each new integral has an increased power of x (this one is x, next x^2, then x^3)! I can see no end!

Have I made yet another mistake?!
 


I don't know how where i was going with that intgral! I started again from scratch following your advice and every thing seemed to fall into place itself so thanks to both of you for your help!:smile:
 

Similar threads

Replies
7
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 14 ·
Replies
14
Views
5K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
24
Views
3K