Not a homwork problem, Fresnel Equations

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SUMMARY

The discussion focuses on deriving the critical angle for internal reflection using both Snell's Law and the Fresnel Equations. The critical angle can be calculated as θ_c = arcsin(n2/n1), where n1 and n2 are the refractive indices of the two media. The equations for reflection coefficients, r(tm) and r(te), are provided, demonstrating that at the critical angle, the transmittance angle θ_t approaches 90 degrees, leading to total internal reflection. The necessity of Snell's Law in this derivation is emphasized, particularly for angles greater than the critical angle.

PREREQUISITES
  • Understanding of Snell's Law and its application in optics
  • Familiarity with Fresnel Equations for reflection and transmission
  • Knowledge of refractive indices and their significance in optics
  • Basic proficiency in trigonometry and angle calculations
NEXT STEPS
  • Study the derivation of Snell's Law and its implications in optics
  • Explore the application of Fresnel Equations in different optical scenarios
  • Investigate the concept of total internal reflection and its practical applications
  • Learn about the role of refractive indices in optical design and engineering
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Students and professionals in physics, optical engineering, and anyone interested in understanding light behavior at interfaces between different media.

Alvis
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Homework Statement


I was just curious, I know you can derive the critical angle using Snell's law..but could you use it using the Fresnel Equations of reflection, both of them?

Homework Equations


|r|=1 internal reflection of light
r(tm)=(n1cos(theta-i)-n2cos(theta-t))/(n1cos(theta-i)+n2cos(theta-t))
r(te)=(n2cos(theta-t)-n1cos(theta-t))/(n1cos(theta-t)+n2cos(theta-i))
I'm putting theta-t and theta-i to denote incident angle and transmittance angle

supposed to arrive at crit angle=arcsin(n2/n1)

The Attempt at a Solution


r(te)=
[(n2cos(theta-t)-n1cos(theta-t))/(n1cos(theta-t)+n2cos(theta-i))]^2=1r(tm)=
[(n1cos(theta-i)-n2cos(theta-t))/(n1cos(theta-i)+n2cos(theta-t))]^2=1
 
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## R=1 ## at the critical angle because ## cos(\theta_t) =0 ## since ## \theta_t=90 \, degrees ##. I think it is necessary to use Snell's law to compute the critical angle ## \theta_i=\theta_c ##. For ## \theta_i ## greater than the critical angle, ## \theta_t ## does not exist. ## \\ ## Note: In your very first equation of part 3, I think the first "theta-t" should be a "theta-i". ## \\ ## Additional note: To get Latex, you need to put " ## " on both sides of the expression.
 
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