MHB Not that Obvious: Missing Numbers In A Table

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The discussion revolves around solving a system of equations derived from a table with missing numbers. Participants work through equations representing the sums of rows and columns, attempting to relate variables to find their values. Various strategies are proposed, including equating sums and subtracting equations to isolate variables. After some back-and-forth, a potential solution emerges, but discrepancies in the calculations prompt a reevaluation of the results. Ultimately, the group aims to confirm the correct values for the variables involved.
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Ive tried to make each variable relate to a but it hasn't worked.View attachment 6511
 

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Re: Not that Obvious

Suppose we let the sum of any row be $S_R$ and the sum of any column be $S_C$, where $S_R\ne S_C$. Using the table, we get the equations:

$$a+157=S_R$$

$$b+c+113=S_R$$

$$d+e+120=S_R$$

$$b+110=S_C$$

$$d+108=S_C$$

$$a+118=S_C$$

$$c+e+54=S_C$$

You now have 7 equations in 7 unknowns...can you proceed?
 
Re: Not that Obvious

You have five equations and five unknowns. Solving this system of equation using any standard technique should work.

Ilikebugs said:
Ive tried to make each variable relate to a but it hasn't worked.
Please describe in more detail what you tried.

Edit: By the five equations I mean equating the sum of the first and second row as well as the sum of the second and third row, and similarly for columns.
 
Re: Not that Obvious

a+157=b+c+113=d+e+120
b+110=d+108=a+118=c+e+54

a=c+b-44=d+e-37
b=a-c+44
c=a-b+44
d=a-e+37
e=a-d+37

a=b+8=d+10=c+e-64

I tried to change each variable to a+ something.
 
Re: Not that Obvious

This is the kind of strategy I would use:

Subtract the second equation from the first to get:

$$a-b=c-44$$

Subtract the 4th from the 6th to get:

$$a-b=-8$$

And so we conclude:

$$c=32$$

Next, observe that the 1st and 3rd equations involve $a,\,d,\,e$ and the 5th and 6th equations involve $a,\,d$...so can you use a similar technique to determine $e$?
 
Re: Not that Obvious

e=47?
 
Re: Not that Obvious

Ilikebugs said:
e=47?

It would help if you show your work...:D
 
Re: Not that Obvious

a+157=SRa+157=SR

b+c+113=SRb+c+113=SR

d+e+120=SRd+e+120=SR

b+110=SCb+110=SC

d+108=SCd+108=SC

a+118=SCa+118=SC

c+e+54=SC

1-3=
a-d-e+37=0
a-d=e-37

6-5=
a-d=10

10=e-37

e=47
 
Re: Not that Obvious

When I subtract the 5th equation from the 6th, I get:

$$a-d=-10$$

Which means:

$$e=27$$

What would you do next?
 
  • #10
Re: Not that Obvious

32+27+54=SC

=113

a=-5
b=3
d=5
 
  • #11
Re: Not that Obvious

Ilikebugs said:
32+27+54=SC

=113

a=-5
b=3
d=5

Yes, that's exactly what I would have done. Good work! (Star)

edit: We've made an error somewhere...the numbers don't add up...however, I have to run now...check the work and see if you can find the error. :D
 
  • #12
Re: Not that Obvious

According to an online calculator, we should find:

$$(a,b,c,d,e)=(-1,7,36,9,27)$$

Let's see if we can get that...(1) - (2):

$$a-b=c-44$$

(6) - (4):

$$a-b=-8$$

Yes, we find:

$$c=36$$

The rest should now fall into place. :D
 

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