Nozzle Energy Balance: Solving Question B

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SUMMARY

The discussion focuses on solving a nozzle energy balance problem, specifically Question B, where the user struggles to derive the correct outlet enthalpy (h2). The user provided initial values: inlet velocity (v1) at 200 m/s, outlet velocity (v2) at 40 m/s, and inlet enthalpy (h1) at 3104.9 kJ/kg. The user calculated an outlet enthalpy (h2) of 22,000 kJ/kg, which contradicts the correct answer of 3128 kJ/kg. The discrepancy arises from misunderstanding the relationship between kinetic energy and enthalpy in the context of energy conservation in nozzles.

PREREQUISITES
  • Understanding of the First Law of Thermodynamics
  • Familiarity with nozzle energy balance equations
  • Knowledge of kinetic and potential energy relationships
  • Basic principles of fluid mechanics
NEXT STEPS
  • Study the First Law of Thermodynamics in the context of fluid systems
  • Learn about energy balance equations specific to nozzles
  • Explore the concept of enthalpy and its calculation in thermodynamic processes
  • Investigate the effects of velocity changes on enthalpy in fluid dynamics
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Students and professionals in mechanical engineering, particularly those focusing on thermodynamics and fluid mechanics, will benefit from this discussion.

Ry122
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Im having difficulty with question b in this problem:
[PLAIN]http://img705.imageshack.us/img705/9484/therm.jpg

Heres my attempt:
m(v1^2)*1/2)+h1)=m(v2^2)*1/2)+h2) + Qout
(v1^2)*1/2)+h1)=(v2^2)*1/2)+h2) + Qout
where v1 = 200ms^1
and v2 = 40ms^-1
and h1 = 3104.9kj/kg
And my answer is 22,000kj/kg for h2.
Can anyone see where I'm going wrong?

The blue writing on the question paper are the correct answers.
 
Last edited by a moderator:
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does anyone know how h = 3128kj/kg
the kinetic energy at the inlet is 20,000kj/kg
while at the outlet it's only 800.
How then could it be that h at the outlet is so low?
Isn't h at the exit dependent on the difference of these kinetic energies?
 

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