What is the significance of Nuclear-Cytoplasmic Ratio in cell aging and cancer?

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SUMMARY

The Nuclear-Cytoplasmic (N/C) Ratio is crucial in understanding cell aging and cancer. As cells age, the N/C ratio decreases from 4:1 to 2:1 due to nuclear shrinkage, leading to disorganized cellular machinery. A high N/C ratio is indicative of cancerous cells, as they maintain a larger nucleus relative to the cytoplasm. Mitosis serves as a mechanism to regulate and maintain the N/C ratio during cellular division.

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Rongeet Banerjee
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TL;DR
My question is 'If the normal Nuclear:Cytoplasmic Ratio of a cell is not maintained then what happens?'
From Wikipedia I have found out that as a cell ages, it's Nucleus shrinks and thus the intial N/C decreases from 4:1 for most cells to 2:1.
I also have a rough idea that Cell machinery becomes unorganised and inefficient.Also high N/C is a characteristic of Cancerous cell.But I do not know the exact reasons.
Finally Mitosis is a direct response to maintain N/C.
Please elaborate more...
 
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It looks like your ratio may be backwards:
N/C = 4:1 would mean the nucleus is larger than the cell that houses it.

Please provides links or references for your several claims:
"as a cell ages, it's Nucleus shrinks"
"unorganised and inefficient"
"high N/C is a characteristic of Cancerous cell"
"Mitosis is a direct response to maintain N/C"
 
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https://en.wikipedia.org/wiki/NC_ratio
👆🏽This link is the reference for the 1st and 3rd claims.
2nd Claim is supported by Guyton and Hall's book of Physiology(which says that the nucleus faces difficulty in controlling it's intercellular proteins)
4th claim is supported by 12th Standard Biology book (NCERT).
 

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