Number of emitted photons per second

In summary, the average wavelength of an LED is 500nm and it emits 300mW of electrical power with an efficiency of 66%. To calculate the number of emitted photons per unit time, the energy of one photon can be multiplied by the overall energy transformed into light, which is equal to 300mJ times 66%. This yields a result of 5x10^17 photons per second.
  • #1
Coldslooks
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Homework Statement


The average wavelength that LED emits is 500nm. The electrical power of the LED is 300mW and the efficiency of turning energy into light is 66%. Number of emitted photons in unit time is?

Homework Equations


##E_f=hcf##
##\frac{Pt}{E_f}=number of photons##

The Attempt at a Solution


After calculating the energy of one photon i am to find the overall energy that is transformed into light. The energy is ##300x10^{-3}J## but how am i to include the efficiency? Just multiply the Energy with 0.66 and use that in the equation? The answer is suppose to yield ##5x10^{17} per second##
 
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  • #2
Coldslooks said:

Homework Equations


##E_f=hcf##
First, this must make no sense. The correct one should be ##E=hf.##
Since you can get the energy of a photon, then given the amount of light you can calculate the number of the photons. Like what you said, the energy transferred to light per second is ##300mJ\cdot 66\%.##
 
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  • #3
tommyxu3 said:
First, this must make no sense. The correct one should be ##E=hf.##
Since you can get the energy of a photon, then given the amount of light you can calculate the number of the photons. Like what you said, the energy transferred to light per second is ##300mJ\cdot 66\%.##
Yeah, your right, i haven't seen that I've put ##c## there, thanks.
Well then, ##\frac{E_t}{E_f}=\frac{198*10^{-3}J}{hf}##
##f=\frac{c}{w}=6*10^{14}## yes the rest is clear thanks :)
 
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