Number of lines equidistant from four points on a plane

Click For Summary
SUMMARY

The discussion revolves around a mathematical problem from the book "Challenging Mathematical Problem with Elementary Solutions," specifically exercise 3 on page 5. The user initially misunderstands the solution regarding the number of lines equidistant from four points on a plane. The clarification provided indicates that in case 1, the configuration involves either four circles or three circles and one straight line, depending on the collinearity of points A, B, and C. The user acknowledges the correction and gains clarity on the solution.

PREREQUISITES
  • Understanding of basic geometric concepts, including circles and lines.
  • Familiarity with collinearity in geometry.
  • Knowledge of mathematical problem-solving techniques.
  • Ability to interpret mathematical texts and exercises.
NEXT STEPS
  • Study the properties of circles and lines in Euclidean geometry.
  • Explore the concept of collinearity and its implications in geometric configurations.
  • Review similar mathematical problems in "Challenging Mathematical Problem with Elementary Solutions."
  • Learn about the relationships between points, lines, and circles in plane geometry.
USEFUL FOR

Mathematics students, educators, and anyone interested in solving geometric problems or enhancing their understanding of spatial relationships in geometry.

mahblah
Messages
19
Reaction score
2
Homework Statement
Four points in the plane are given, not all on the same straight line, and not all on a circle. How many straight lines and circles can be drawn which are equidistant from these points?
Relevant Equations
by distance from a point P to a circle c with center O we mean the lenght of the segment PQ, where Q is the point where the ray from O in the direction OP meets c
Hi, i'm trying to solve this problem.

It's exercise 3 on page 5 from this book:
Challenging mathematical problem with elementary solutions

The solution is on page 41:

1683625713913.png

1683626064255.png


I'm OK with the 4 circles in case 1: i can pick (inside/outside):
ABC + D,
ABD + C,
ADC + B,
BCD + A.
What i cannot understand is how there can be 4 straight lines in case 1:
if three points stand on one side of the equidistant line, these point must be collinear, and so there is only one possible straight line (i cannot re-arrange them!)

1683626234473.png


where am I wrong?

thanks
 
Physics news on Phys.org
The phrasing of the answer lead to a misunderstanding. It is never four straight lines, it is either four circles or three circles and a straight line. If A, B, and C are collinear, then you can draw a straight line as you did, and three circles concentric with the circles passing through ABD, ACD, and BCD.
 
  • Like
Likes   Reactions: mahblah
Oh that makes sense
Thanks!
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
5K
Replies
7
Views
2K
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 25 ·
Replies
25
Views
3K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K