Number of lines equidistant from four points on a plane

AI Thread Summary
The discussion revolves around a mathematical problem involving the number of lines equidistant from four points on a plane. The user initially misunderstands the solution, believing there are four straight lines when, in fact, the answer involves either four circles or a combination of three circles and one straight line. Clarification is provided that if three points are collinear, only one straight line can be drawn, along with three concentric circles. The user expresses gratitude for the clarification, indicating that the explanation resolved their confusion. The conversation highlights the importance of precise language in mathematical problem-solving.
mahblah
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Homework Statement
Four points in the plane are given, not all on the same straight line, and not all on a circle. How many straight lines and circles can be drawn which are equidistant from these points?
Relevant Equations
by distance from a point P to a circle c with center O we mean the lenght of the segment PQ, where Q is the point where the ray from O in the direction OP meets c
Hi, i'm trying to solve this problem.

It's exercise 3 on page 5 from this book:
Challenging mathematical problem with elementary solutions

The solution is on page 41:

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I'm OK with the 4 circles in case 1: i can pick (inside/outside):
ABC + D,
ABD + C,
ADC + B,
BCD + A.
What i cannot understand is how there can be 4 straight lines in case 1:
if three points stand on one side of the equidistant line, these point must be collinear, and so there is only one possible straight line (i cannot re-arrange them!)

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where am I wrong?

thanks
 
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The phrasing of the answer lead to a misunderstanding. It is never four straight lines, it is either four circles or three circles and a straight line. If A, B, and C are collinear, then you can draw a straight line as you did, and three circles concentric with the circles passing through ABD, ACD, and BCD.
 
Oh that makes sense
Thanks!
 
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