Number of molecular hits from air onto a surface

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SUMMARY

The discussion focuses on calculating the average number of molecular hits per unit time on a surface exposed to air, specifically using the ideal gas law and relevant equations. The participant assumed standard conditions of 293 K and 101325 Pa, leading to a calculated concentration of 2.67E25 particles/m³. Despite arriving at an answer of 8.75E24 hits per second, the expected result is approximately 2.00E24 hits per second. The participant seeks clarification on their approach and the accuracy of their calculations.

PREREQUISITES
  • Understanding of the ideal gas law and its applications
  • Familiarity with angular averaging in physics
  • Knowledge of basic thermodynamics, particularly pressure and temperature relationships
  • Ability to perform calculations involving molar mass and particle concentration
NEXT STEPS
  • Review the derivation and application of the ideal gas law in molecular collision problems
  • Study angular averaging techniques in statistical mechanics
  • Learn about the relationship between pressure, temperature, and molecular speed in gases
  • Explore detailed examples of calculating molecular hits on surfaces in various gas conditions
USEFUL FOR

Students in physics or chemistry, particularly those studying gas behavior and molecular dynamics, as well as educators seeking to clarify concepts related to molecular collisions and ideal gas laws.

mr-serendip
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Homework Statement


Compute the average number of molecular hits, per unit time, experienced by a square inch of surface exposed to air, under normal conditions. Assume air is a mixture composed of 80% N2, 20% O2, both of which are assumed to be ideal gases. You will have to perform angular averaging. You will also need to know the average speed, |v| of a molecule. If you know how to compute it, go ahead and do it. Otherwise, you may simply pretend that |v|= <v^2>1/2. Give answer in units of inverse seconds

Homework Equations


F=1/ 3* m<v^2> n S S=area of surface
P=1/ 3* m<v^2> n m=mass of particle n= concentration of particles
p=nKbT Nconctact = nvtS

The Attempt at a Solution


I've assume 293 degrees K and 101325 Pa
I've set both equations of pressure equal to each other and I get down to 2.67E25 particles / m^3
I then plug into the Ncontact equation the concentration I've found of particles, along with the area of the surface, and the average velocity. I'm not sure about this assumption but For my calculations for the molar mass I did .8*28+.2*32=28.8 g = .0288 kg.
For my answer I got 8.75E24 hits per unit second.
I do know that the answer is about 2.00E24 hits per unit second.
I'm not sure where I could have went wrong, I'm not sure if I am approaching this problem correctly or using the correct equations but I did get fairly close, which could be luck also. I would appreciate help, I've been stuck on this for a while now. Thanks
 
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