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Number of Turns/Circular Motion

  1. Jan 7, 2015 #1
    vJljG.jpg
    eiEs8.jpg

    Having problems with (b)(iiI).

    I've tried using the kinetic energy value = work done and dividing that by torque.

    I've also tried used the other circular motion formulas but haven't had any success.

    Attempt:

    Wd = θ x T

    Ek(from b ii) = Wd

    θ = 2278.29/0.6
    = 3797 turns
     
    Last edited: Jan 7, 2015
  2. jcsd
  3. Jan 7, 2015 #2

    SteamKing

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    Show us what you've tried.
     
  4. Jan 7, 2015 #3
    I've added what I tried.
     
  5. Jan 7, 2015 #4

    BvU

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  6. Jan 7, 2015 #5
    I'm asking about a different question here, previous one was in regards to (b) (i), this is (b)(iii).
     
  7. Jan 12, 2015 #6

    CWatters

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    Two errors..

    1)Typo.. 2278.29 should be 2778.29
    2) Check the units of angular displacement θ. (Hint: it's not turns)
     
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