Number of Turns/Circular Motion

  • Thread starter smr101
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  • #1
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vJljG.jpg

eiEs8.jpg


Having problems with (b)(iiI).

I've tried using the kinetic energy value = work done and dividing that by torque.

I've also tried used the other circular motion formulas but haven't had any success.

Attempt:

Wd = θ x T

Ek(from b ii) = Wd

θ = 2278.29/0.6
= 3797 turns
 
Last edited:

Answers and Replies

  • #2
SteamKing
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Show us what you've tried.
 
  • #3
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Show us what you've tried.

I've added what I tried.
 
  • #5
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I'm asking about a different question here, previous one was in regards to (b) (i), this is (b)(iii).
 
  • #6
CWatters
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θ = 2278.29/0.6 = 3797 turns

Two errors..

1)Typo.. 2278.29 should be 2778.29
2) Check the units of angular displacement θ. (Hint: it's not turns)
 

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