- #1
smr101
- 72
- 0
How is the polar moment of inertia in a rod calculated?
Thanks.
Thanks.
Since there is no context whatsoever in the original posting, it's difficult to assist any further here.
Well, at least now I can understand your confusion. However, it doesn't literally ask for the polar moment of inertia (a.k.a area moment of inertia), but for the polar mass moment of inertia. I see that used for the rotational moment of inertia, so with the context of b (ii) and b(iii) that seems the most logical choice.
Can't imagine you haven't seen it before ! What did you use for 4a ?
## I=\int dI = {\displaystyle \int_0^M r^2 \; dm}##
Can't imagine you haven't seen it before ! What did you use for 4a ?
## I=\int dI = {\displaystyle \int_0^M r^2 \; dm}##