Number of ways to make delegations

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Two methods for calculating the number of ways to make delegations were discussed. Method (1) correctly calculates the total ways minus delegations of all men and all women, resulting in 120 combinations. Method (2) incorrectly counts some combinations multiple times, leading to an inflated total of 420. The redundancy arises when different selections yield the same group, which is not accounted for in Method (2). The conclusion is that Method (1) is the accurate approach for this problem.
songoku
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Homework Statement
Find number of ways to make delegations of 4 from 4 men and 5 women if there is at least one man and one woman
Relevant Equations
Permutation and Combination
I did it 2 ways:

(1) No. of ways = total ways - delegations of all men - delegations of all women = 9C4 - 4C4 - 5C4 = 120

(2) No. of ways = choosing one man x choosing one woman x choosing the other two people = 4C1 x 5C1 x 7C2 = 420

I am pretty sure method (1) is correct but I don't understand why method (2) is wrong

Thanks
 
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Method 2 counts some combinations more than once. E.g. if I first select man A and woman A, then from the remaining 7 take man B and woman B, the result is the same as if I first select man B and woman B, then from the remaining 7 take man A and woman A. (Or A/B then B/A, or B/A then A/B). But each of these counts separately in method 2.
 
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mjc123 said:
Method 2 counts some combinations more than once. E.g. if I first select man A and woman A, then from the remaining 7 take man B and woman B, the result is the same as if I first select man B and woman B, then from the remaining 7 take man A and woman A. (Or A/B then B/A, or B/A then A/B). But each of these counts separately in method 2.
Thank you very much mjc123
 
The working out suggests first equating ## \sqrt{i} = x + iy ## and suggests that squaring and equating real and imaginary parts of both sides results in ## \sqrt{i} = \pm (1+i)/ \sqrt{2} ## Squaring both sides results in: $$ i = (x + iy)^2 $$ $$ i = x^2 + 2ixy -y^2 $$ equating real parts gives $$ x^2 - y^2 = 0 $$ $$ (x+y)(x-y) = 0 $$ $$ x = \pm y $$ equating imaginary parts gives: $$ i = 2ixy $$ $$ 2xy = 1 $$ I'm not really sure how to proceed from here.