lagrange's interpolation formula anyone? (i.e. you can find a (unique) polynomial f(n) of degree ≤ 6 that will give you these 6 numbers for n = 1,...6, and as next number f(7) = any result you want.)
e.g. [(x-1)(x-2)...(x-6)]/[(7-1)(7-2)...(7-6)] equals 1 at x=7 and equals zero at x=1,...6. doing this for each number 1,...7, we can multiply each term by what ever we want, add the results, and get a polynomial that has arbitrary values at x=1,...,7. i.e. just as a linear functionn can pass through any two points with distinct x - coordinates, so also can a 6th degee polynomial pass throug any 7 such points.
So if you are trying to come up with a polynomial rule, this method seems to gives the simplest one possible.
but you can make up any rule you want, like 83 80 84 83 88 95 83 102 112 83 122 135 83 148 164 83...