Number Theory: Divisibility and Prime Factorization

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SUMMARY

The discussion centers on the proof that m² is divisible by 3 if and only if m is divisible by 3, a fundamental concept in number theory. The user demonstrated the proof by assuming m = 3k and showing that m² = 9k², thus confirming that 3 divides m². Conversely, the user explored a proof by contradiction, indicating that if 3 does not divide m, the prime factorization of m² would not include 3, leading to a contradiction. This establishes the equivalence definitively.

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alexfresno
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{SOLVED}Number theory/ divisibility

Show that m^2 is divisible by 3 if and only if m is divisible by 3.

MY attempt:

I assumed that 3k=m for some integers k and m.
squared both sides and now get.

3n=m where n=3*(3k^2). Thus 3|m^2

Now the problem is when i assume:
3k=m^2 and need to show 3|m.
 
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The easiest way seems to be via contradiction. If 3k = m^2 but 3 does not divide m, then what do you know about the prime factorization of m^2?
 

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