
Limited time only! Sign up for a free 30min personal tutor trial with Chegg TutorsDismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!
Number theory: gcd(a,b)=1 => for any n, gcd(a+bk,n)=1 for some k
 Similar Discussions: Number theory: gcd(a,b)=1 => for any n, gcd(a+bk,n)=1 for some k

If lcm(a,b) = ab, why is gcd(a,b) = 1? (Replies: 4)

Gcd(m, n)=1 implies Zmn isomph to Zm x Zn (Replies: 9)

Prove GCD(a+b,ab) = 1 or 2 (Replies: 3)

Prove gcd(nn!, n!+1)=1 (Replies: 1)

Number Theory. If d=gcd(a,b) then (Replies: 1)
Loading...