Object Beneath the Water Problem

[x31fighter]

Homework Statement

A small logo is embedded in a thick block of transparent material (n = 1.81), 4.03 cm beneath the top surface of the block. The block is put under water (n = 1.333), so there is 2.15 cm of water above the top surface of the block. The logo is viewed from directly above by an observer in air. How far beneath the top surface of the water does the logo appear to be?

Homework Equations

apparent depth = d ((n_2)/(n_1))

The Attempt at a Solution

First was 4.03(1.33/215) it was wrong.

 

[technician]

For the block in water I used n2/n1 = real/apparent depth.
n2 is the block, n1 is the water. I got 2.96cm as the point in the block from which the light appears to come from into the water.
You can now take this point to be at a depth of 2.15 + 2.96 in WATER
then do n2/n1 = real/ apparent again ( I got 4.58cm from water surface)