Complex apparent and real depth problemm

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pistonsfan321
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Homework Statement



A small logo is embedded in a thick block of transparent material (n = 1.73), 3.59 cm beneath the top surface of the block. The block is put under water (n = 1.333), so there is 1.86 cm of water above the top surface of the block. The logo is viewed from directly above by an observer in air. How far beneath the top surface of the water does the logo appear to be?


Homework Equations



apparent depth = dn_2/(n_1)

The Attempt at a Solution



What i tried doing is applying this equation twice. First with glass and water 3.59(1.33/1.73). Then with water and air 1.86(1/1.33). After that I added the two values of the apparent distances which I got 4.162
 
pistonsfan321 said:
What i tried doing is applying this equation twice. First with glass and water 3.59(1.33/1.73).
OK. That's the apparent location of the first image below the block surface. What's the location of that image below the water surface? That's the distance you want when using the equation the second time.