(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A plane is dropping an object from a height of 227m, such that it lands at a group of people on the ground. The speed of the plane is 60 m/s. How many meters before the group does the plane have to drop the object such that it lands at their position?

2. Relevant equations

x_{f}= x_{i}+ v_{ix}delta t + (1/2) a_{x}(delta t)^{2}

3. The attempt at a solution

From my understanding, I need to break up the x and y components of this problem. If I can find the time it takes the object to hit the ground, I can multiply it by the plane's velocity and see what distance the plane must be from the observers for the package to hit its target.

227 m = 9.8t m/s^2

(227 m)/(9.8 m/s^2) = t

t^2 = 23.162

t = sqrt(23.162)

t = 4.813 seconds

Now that I have the time it took for the object to fall, I can multiply it by the plane's velocity to see how far in the x direction the object will travel in 4.813 seconds:

4.813 s * 60 m/s = 288.78 m

This is the answer I get, but it isn't correct. I can't see how multiplying the velocity by the time is wrong, but perhaps I have the wrong time?

Thanks,

x^2

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# Homework Help: Object dropped from plane - where does it land?

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