Observing Proton Decay & Antineutrinos

Click For Summary
SUMMARY

This discussion centers on the complexities of observing proton decay and the role of antineutrinos in such experiments. It establishes that proton decays do not result in neutrons, and the current Standard Model of particle physics does not predict proton decay. The Super-Kamiokande experiment utilizes a method to distinguish between positrons from proton decay and those from neutrino interactions, employing a veto on neutron detection to reduce background noise. Ultimately, the findings indicate that while two events were recorded, they align with expected background levels, preventing definitive conclusions about proton decay.

PREREQUISITES
  • Understanding of the Standard Model of particle physics
  • Familiarity with inverse beta decay (IBD) processes
  • Knowledge of particle detection methods, specifically in high-energy physics
  • Experience with data analysis in experimental physics
NEXT STEPS
  • Research the Glashow-Salam-Weinberg model and its implications for proton decay
  • Study the methodology of the Super-Kamiokande experiment, particularly arXiv:1610.03597
  • Explore techniques for reducing background noise in particle detection experiments
  • Investigate alternative decay modes of baryons and their experimental signatures
USEFUL FOR

Particle physicists, researchers in high-energy physics, and students studying the implications of proton decay and neutrino interactions will benefit from this discussion.

swampwiz
Messages
567
Reaction score
83
antineutrino?

I was looking at this article, which says that a proton that interacts with an antineutrion transforms (or whatever the proper verb is here) into a neutron & positron. But this begs the question that if we're trying to observe a proton decaying, how would we know that it had not interacted with an antineutrino?

https://en.wikipedia.org/wiki/Inverse_beta_decay
 
Physics news on Phys.org
First, proton decays are not to neutrons, so if you have perfect knowledge of your final state you know what happened. Practically that won't be the case however, so indeed you won't know what happened in an individual event.
In general, most experiments have some background that you need to be able to handle. If you are looking for proton decay by counting positrons you are essentially asking "do we see more positrons then we would expect from neutrino+proton interactions (+ other backgrounds)". If you can detect neutrons you can use this to keep the background lower.
 
  • Like
Likes   Reactions: ohwilleke and topsquark
Proton decays are also very model-dependent, what the final states are
 
  • Like
Likes   Reactions: dextercioby, ohwilleke, Vanadium 50 and 1 other person
current theory doesn't have proton decay.
 
  • Like
Likes   Reactions: vanhees71 and ohwilleke
mathman said:
current theory
What you mean is that there are no proton decays in the Standard Model of particle physics (Glashow-Salam-Weinberg model).
 
  • Like
Likes   Reactions: vanhees71
malawi_glenn said:
What you mean is that there are no proton decays in the Standard Model of particle physics (Glashow-Salam-Weinberg model).
Also there is no experimental evidence for it.
 
  • Like
Likes   Reactions: vanhees71 and swampwiz
As others have written, few experiments claim discovery after one event. Lots of things can happen at that level. Also, as others have mentioned, these decays are model dependent.

As such, the question, "Gosh, couldn't you just get confused?" is so broad as to be unanswerable. If the decay you are looking for is p \rightarrow \pi^0 e^+ which is a common one in many models, it gives you a monoenergetic and high-energy positron, a neutral pion, and no neutron. That is distinguishable from IBD where you get no pion, a neutron, and a lower energy positron with variable energy.

You can repeat this exercise for your favorite supposed decay modes.
 
  • Like
Likes   Reactions: vanhees71 and berkeman
Dr.AbeNikIanEdL said:
First, proton decays are not to neutrons, so if you have perfect knowledge of your final state you know what happened. Practically that won't be the case however, so indeed you won't know what happened in an individual event.
In general, most experiments have some background that you need to be able to handle. If you are looking for proton decay by counting positrons you are essentially asking "do we see more positrons then we would expect from neutrino+proton interactions (+ other backgrounds)". If you can detect neutrons you can use this to keep the background lower.
Or in other words, it is a matter of completeness and certainty of your knowledge of the final state. Searching for a proton decay might be a matter of distinguishing between "we can detect neutrons, but sometimes we miss them, so this was just another time when we missed a neutron" vs. "we are massively unlikely to miss a neutron, so if we did not see it, this must have been the time when baryon really decayed for good". Since baryon decay is certainly a rare process, can you really rule out just missing a neutron to that probability?

Many searches for proton decay are looking for high energy products, like fast positron or pion, on the guess that a large fraction of proton rest mass turns into energy. The same products might be produced by energetic neutrinos - but then especially the neutron would also tend to get a large recoil energy, and be easy to detect.
 
  • Like
Likes   Reactions: swampwiz
snorkack said:
"we can detect neutrons, but sometimes we miss them, so this was just another time when we missed a neutron" vs. "we are massively unlikely to miss a neutron, so if we did not see it, this must have been the time when baryon really decayed for good"
But what's actually done is intermediate between these two. Let's for concreteness look at the Super-Kamiokande analysis (arXiv:1610.03597). They basically say "we know how often we see electrons from neutrino interactions, so if we see significantly more than that some of those have to come from proton decay". Of course, electrons here means "electrons looking like they come from a proton decay" which gets rid of backgrounds. But only in their last run period do they actually have an explicit veto on neutrons (you can see from table 1 this reduces their background by a factor of ~2). At the end of the day they even see two events (in the muon channel). This is compatible with their expected background expectation, but they don't make a definite claim what those events are.
 
  • Like
Likes   Reactions: vanhees71

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K