Obtain the time constant from a transfer function

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To calculate the time constant from the transfer function G(s) = s/(6.25+s), one must identify the system's poles, which are derived from the denominator. The time constant is typically associated with the pole at s = -6.25, giving a time constant of 6.25 seconds. For sketching a Bode plot, it is appropriate to express the transfer function as s * (1/(6.25+s)), allowing for easier analysis of the system's frequency response. The discussion also hints at the possibility of this being an academic exercise. Understanding these concepts is crucial for effective system analysis and design.
rusty009
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Hey, say I have a transfer function,

G(s) = s/(6.25+s)

How would I calculate the time constant for this transfer function? Also, if I wanted to sketch a bode plot for this transfer function, would I split it up into s* 1/(6.25+s) ?

Thanks in advance.
 
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rusty009 said:
Hey, say I have a transfer function,

G(s) = s/(6.25+s)

How would I calculate the time constant for this transfer function? Also, if I wanted to sketch a bode plot for this transfer function, would I split it up into s* 1/(6.25+s) ?

Thanks in advance.

Is this for school?
 
What mathematics software should engineering students use? Is it correct that much of the engineering industry relies on MATLAB, making it the tool many graduates will encounter in professional settings? How does SageMath compare? It is a free package that supports both numerical and symbolic computation and can be installed on various platforms. Could it become more widely used because it is freely available? I am an academic who has taught engineering mathematics, and taught the...

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