Alright, my brains a little shot right now so I need some help. I've been studying the Casino game of Roulette and I was curious how this idea would work out. Lets say you put in $20 each time and there are 2 different systems. 1st way: 50% chance to win back what you put in. So your original $20 + $20. 2nd way: 66% chance to win back half what you put in. So your original $20 + $10. Either way the max you could lose is $20 yet the 2nd way you would be risking more for less. Over the course of lets say 10 turns doing the same way each time, which system would provide the best results?? From what I've gathered: [edit: Revised the work below in post #3.] Method 1 would give roughly 5 wins. 5 wins = $40 per win = $200 5 loses = $-20 per loss = $-100 In this method, you win $100 roughly. Method two, you'd expect around 6.66 wins. 6.66 wins = $30 per win = $199.8 3.34 losses = $66.8 210 - 60 = $133 Yet there has to be a flaw somewhere, that would increase the odds of winning to over 50% for method two..