On-Axis Field of a Uniformly Magnetized Sphere

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SUMMARY

The discussion focuses on calculating the on-axis magnetic field of a uniformly magnetized sphere using the Biot-Savart law. The initial approach involved direct integration, which led to an elliptic integral solution, differing from the results presented in Griffiths' textbook. Key errors identified include a misrepresentation of the angle in the diagram and the incorrect use of the sine function's exponent, where ##\sin^3{\theta}## should replace ##\sin^4{\theta}##. Participants suggest that integrating by parts may resolve the remaining issues in the calculation.

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Homework Statement
Find the magnetic field of a sphere along the axis of magnetization
Relevant Equations
$$\vec{B}=\frac{\mu_0}{4\pi}\int\frac{\vec{K}\times\hat{r}}{|\vec{r}|^2}da$$
$$\vec{K}=\vec{M}\times\hat{n}$$
Since I am only required to find the on-axis field, I tried directly integrating the biot savart to find the field, rather than integrating to find the vector potential before taking the curl.
20191126_142106.jpg

However, on integration (by mathematica) it seems that the solution is an elliptic integral, very different from what griffiths has found in his book. Can someone find the issue in my working? Thanks!
 
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I found one error on the left side. You got a little sloppy with your diagram. ## x \neq R \cos{\theta} ##. ## \ ## Edit: Scratch that. I need to study this more...## \\ ## I think your last line should have ## \sin^3{\theta} ##, instead of ## \sin^4{\theta} ##.## \\ ## Writing ##\sin^3{\theta} \, d \theta=(1-cos^2{\theta}) \, d(\cos{\theta})=(1-u^2) \, du ##,## \\ ## I think you will find the ## u^2/(denominator) ## can be integrated by parts. ## \\ ## Doing it slightly differently, I also got a ## \sin^3{\theta} ## instead of ## \sin^4{\theta} ##. That may be your only error.
 
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