On-shell renormalization (Srednicki ch31)

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SUMMARY

In the discussion on on-shell renormalization in \phi^4 theory, the self-energy is derived as \(\Pi(k^2)=\frac{\lambda}{2(4\pi)^2} \left[ \frac{2}{\epsilon}+1+\ln\left(\frac{\mu}{m^2}\right)\right]m^2-Ak^2-Bm^2\). The user attempts to impose the on-shell conditions \(\Pi(-m^2)=0\) and \(\Pi'(-m^2)=0\) but encounters confusion leading to the conclusion that \(\Pi(k^2)=0\) at one loop in the on-shell scheme. The discussion clarifies that this outcome is expected and not indicative of an error in the calculations.

PREREQUISITES
  • Understanding of \phi^4 theory and its self-energy calculations
  • Familiarity with on-shell renormalization conditions
  • Knowledge of the Lehman-Callen form of propagators
  • Basic proficiency in handling divergences and regularization techniques
NEXT STEPS
  • Study the derivation of self-energy in \phi^4 theory using Srednicki's methods
  • Explore the implications of on-shell renormalization in quantum field theory
  • Learn about the Lehman-Callen representation of propagators
  • Investigate regularization techniques to handle divergences in quantum field theories
USEFUL FOR

The discussion is beneficial for theoretical physicists, particularly those specializing in quantum field theory, and students seeking to understand renormalization techniques in \phi^4 theory.

LAHLH
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Hi,

In \phi^4 theory, Srednicki deduces the self energy (equation 31.5), as:
\Pi(k^2)=\frac{\lambda}{2(4\pi)^2)} \left[ \frac{2}{\epsilon}+1+ln\left(\frac{\mu}{m^2}\right)\right]m^2-Ak^2-Bm^2

I understand how he gets to this just fine, but now I'm trying to impose the usual on-shel (OS) renormalization scheme, which I believe means \Pi(-m^2)=0 and \Pi'(-m^2)=0 (Which are due to needing the exact prop to have poles and residues in correspondance with the Lehman-Callen form of it).

I'm having some issues doing this and I really don't understand why. Firstly I set (to remove the mu depedence and the 1/epsilon infinity) :

B=\frac{\lambda}{16\pi^2}\left[ \frac{1}{\epsilon}+\frac{1}{2}+\kappa_B+ln\left(\frac{\mu}{m^2}\right)\right].

Thus

\Pi(k^2)=-\frac{\lambda}{16\pi^2}\kappa_Bm^2-Ak^2

But now, imposing \Pi(-m^2)=0 leads to:

A=\frac{\lambda}{16\pi^2}\kappa_B

So,

\Pi(k^2)=-\frac{\lambda}{16\pi^2}\kappa_B(m^2+k^2)

Finally, imposing \Pi'(-m^2)=0 leads to:

-\frac{\lambda}{16\pi^2}\kappa_B=0

and thus \Pi(k^2)=0

I really don't know what I'm doing that could be possibly wrong. Appreciate any help whatsoever, thanks.
 
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There's nothing wrong. Pi(k^2)=0 at one loop in the OS scheme.
 
Avodyne said:
There's nothing wrong. Pi(k^2)=0 at one loop in the OS scheme.

Oh, I see, I thought that must have meant I had made a mistake. Thanks very much Avodyne
 

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