[SOLVED] once more with feeling! another ideal gas question. the pressure inside a sealed can which is kept in a deep freeze at -23C is 0.8x10^5 N/m^2. If the can is placed in water of temperature 27C: calculate the increase in pressure inside the can. initially, pressure/temperature = 0.8x10^5 / 273-23 =320 afterwards, pressure 2 divided by (273+27) must equal 320 also. this gives pressure 2 as 96000Pa increase in pressure = 0.8x10^5 - 96000 = -16000 but if the temperature increases, surely the pressure has to increase? since they are directly proportional?? or have i taken them away the wrong way round?