1. The problem statement, all variables and given/known data A 60kg student lowers herself down 40m at a constant speed of 1.0 m/s. The chair has a mass of 35kg. Find the force of the rope. (See image) 2. Relevant equations I was using force equations in attempts to solve for the problem. 3. The attempt at a solution Fchair+Fstudent-Frope-Frope=m(a) 35(9.8)+60(9.8)-2Frope=95(0) 343+588-2Frope=0 2Frope=931 Frope=465.5N Although the answer I got above was 465.5N, the answer listed in the back of the book was Frope=490N. I am at a complete loss as to what I am doing wrong here? I did a similar problem where the person was traveling upwards like this at a constant velocity and got it right. Not sure what changed here that I am not taking into consideration? I am also curious after having done a similar problem, since the force is split into 2 parts, the force quantity for the rope would be the value for each rope individually, correct (one attached to chair and the one held by the student)? I just want to make sure I am understanding this correctly. Also, if that is the case, then if I were asked what the total force being applied to the rope was, it would be double the value to account for each side being pulled, correct?