- #1
ac7597
- 126
- 6
- Homework Statement
- Joe puts on his skis and heads for the slopes. A fresh layer of new snow has fallen, making the coefficient of kinetic friction between his skies and the snow only μk=0.037. He heads for the Starlight Run, which features a long slope at a constant angle of θ=17.8 degrees above the horizontal.
The resort has a new device to bring skiers to the top of the run: instead of a chair lift or a moving rope, a large cylinder sits at the base of the hill. Skiers crouch down and slide into the cylinder, then press a button. Compressed gas shoots the skier out of the cylinder with an initial speed v=30.3 m/s, and they slide up the hill.
How far up along the slope will Joe slide before coming to a momentary halt?
How long will it take him to reach the peak of his motion?
After coming to a momentary halt, Joe starts to slide down the hill. How long will it take him to reach the bottom?
- Relevant Equations
- g=9.8 m/s^2
Homework Statement: Joe puts on his skis and heads for the slopes. A fresh layer of new snow has fallen, making the coefficient of kinetic friction between his skies and the snow only μk=0.037. He heads for the Starlight Run, which features a long slope at a constant angle of θ=17.8 degrees above the horizontal.
The resort has a new device to bring skiers to the top of the run: instead of a chair lift or a moving rope, a large cylinder sits at the base of the hill. Skiers crouch down and slide into the cylinder, then press a button. Compressed gas shoots the skier out of the cylinder with an initial speed v=30.3 m/s, and they slide up the hill.
How far up along the slope will Joe slide before coming to a momentary halt?
How long will it take him to reach the peak of his motion?
After coming to a momentary halt, Joe starts to slide down the hill. How long will it take him to reach the bottom?
Homework Equations: g=9.8 m/s^2
I made a component diagram of the forces acting on the skier. I got a horizontal force equation as m(ax) = F - u(cos17.8)mg-sin(17.8)mg, but am confused on how to proceed forward.
The resort has a new device to bring skiers to the top of the run: instead of a chair lift or a moving rope, a large cylinder sits at the base of the hill. Skiers crouch down and slide into the cylinder, then press a button. Compressed gas shoots the skier out of the cylinder with an initial speed v=30.3 m/s, and they slide up the hill.
How far up along the slope will Joe slide before coming to a momentary halt?
How long will it take him to reach the peak of his motion?
After coming to a momentary halt, Joe starts to slide down the hill. How long will it take him to reach the bottom?
Homework Equations: g=9.8 m/s^2
I made a component diagram of the forces acting on the skier. I got a horizontal force equation as m(ax) = F - u(cos17.8)mg-sin(17.8)mg, but am confused on how to proceed forward.