One-dimensional motion with constant acceleration

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A falling object covers one-fourth of its total distance in the last second of its fall, prompting a calculation of its initial height. The problem requires the application of equations of motion for constant acceleration to determine the height from which the object was dropped. Key variables include the total distance fallen and the time taken for the fall. The solution involves setting up equations that relate distance, time, and acceleration due to gravity. Ultimately, the problem emphasizes the relationship between distance traveled and time in uniformly accelerated motion.
tja2468
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Homework Statement


A falling object travels one-fourth of its total distance in the last second of its fall. From what height was it dropped?


Homework Equations



equations of motion for constant acceleration



Thanks in advance !
 
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tja2468 said:

Homework Statement


A falling object travels one-fourth of its total distance in the last second of its fall. From what height was it dropped?

Homework Equations



equations of motion for constant acceleration
Thanks in advance !
You seem to have omitted a vital section,
Homework Template said:

The Attempt at a Solution

 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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