1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

One more Vector problem and we are good to go

  1. Sep 25, 2006 #1
    One more Vector problem and we are good to go!!!

    The Problem:
    Find the change in velocity of a yacht if it changes its velocity from
    5ms^-1 due north to 3ms^-1 due west and also state its direction.

    The solution :
    (resultant vel.)^2 = 5^2 + 3^2 = 5.8 ms^-1
    direction = tan-1(3/5) = 31 degrees west of north

    However , the books answer is 5.8 ms^-1 in a direction 31 degrees west of south . what am i doing wrong here ???
     
  2. jcsd
  3. Sep 25, 2006 #2

    radou

    User Avatar
    Homework Helper

  4. Sep 25, 2006 #3
    I did draw it but unless south means up and norths means down on paper I dont know what ur getting at lolz I wanna tear my book apart !!!!!!
     
  5. Sep 25, 2006 #4
    err .... got it !!! im so embarrased !!!

    thank you !!! :)
     
  6. Sep 25, 2006 #5

    radou

    User Avatar
    Homework Helper

    [tex]\vec{v}_{1}[/tex] is pointing north (up). [tex]\vec{v}_{2}[/tex] is pointing west (left). [tex]\vec{v}_{2}-\vec{v}_{1}[/tex] is then pointing south-west.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: One more Vector problem and we are good to go
  1. One more trig problem (Replies: 10)

  2. One more on vectors (Replies: 2)

  3. One more problem (Replies: 1)

Loading...