- #1

zendani

- 15

- 0

Hi

the image of an open set by a function continues IS an open set?

i think that if we have a constant function , the image of an open set does not have to be open.

the image of an open set by a function continues IS an open set?

i think that if we have a constant function , the image of an open set does not have to be open.

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