MHB Operator form of integro-differential equation

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The discussion focuses on the representation of the Fredholm integral equation of the second kind in a simplified operator form. The integral equation is expressed as ψ = f + Kψ, where K is the operator kernel. A participant inquires whether an integro-differential equation can similarly be expressed in operator form. The response confirms that this transformation is indeed possible, affirming the inquiry. The exchange highlights the ability to simplify complex equations into more manageable operator forms.
sarrah1
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Hi

For brevity one usually writes Fredholm integral equation of the 2nd kind

$\psi(x)=f(x)+\int_{a}^{b} \,k(x,s)\psi(s) ds$

into the form

$\psi=f+K \psi$
where $K$ is the operator kernel

My question can one write an integro differential equation

$\d{\psi(x)}{x}=f(x)+\int_{a}^{b} \,k(x,s)\psi(s) ds$

into the form

${D}_{x}\psi=f+K \psi$

thanks
 
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Yep. You just did!
 
Ackbach said:
Yep. You just did!

thank you indeed
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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