Optical and acoustic modes

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Discussion Overview

The discussion centers on the nature of optical and acoustic phonon modes in crystals, particularly focusing on the conditions under which these modes exist and the implications of having multiple atoms per primitive unit cell. Participants explore the relationship between unit cell structure, degrees of freedom, and the characteristics of phonon modes.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants assert that optical and acoustic modes depend on having more than one atom per primitive basis, with optical modes involving neighboring atoms oscillating out of phase.
  • Others question the necessity of multiple atoms for optical modes, suggesting that neighboring atoms could oscillate relative to each other regardless of unit cell composition.
  • One participant highlights that a single atom per unit cell limits the degrees of freedom, affecting the types of phonon modes that can exist.
  • Another participant explains that optical modes require different masses or charges for atoms to oscillate out of phase, which is not possible with a single atom per unit cell.
  • A later reply discusses the energy differences between optical and acoustic phonons, attributing higher energy in optical modes to stronger internal vibrations within molecules compared to intermolecular forces.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of multiple atoms per primitive cell for the existence of optical modes, indicating that the discussion remains unresolved with multiple competing perspectives.

Contextual Notes

Participants reference concepts such as degrees of freedom and the implications of unit cell structure on phonon behavior, but the discussion does not resolve the underlying assumptions or definitions that may affect these interpretations.

aaaa202
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Basically phonons in crystals can either be acoustic or optical according to my book. But then it stresses that a necessary condition for this to hold is that the crystal has more than atom per primitive basis. The optical modes are then when neighbouring atoms oscillate out of phase (i.e. no motion of the center of mass) and the acoustical mode is the exact opposite. But I don't understand why it is so crucial that the crystal has two or more atoms per primitive basis. Can't optical and acoustical modes happen between neighbouring atoms regardless of this?
 
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If there is only one atom per unit cell, how many degrees of freedom are available?

The unit cell is the repeating unit of a crystal; you should be able to define everything that occurs in the crystal in terms of the unit cell - this is especially convenient if you move to the reciprocal space.
 
I don't understand what you are hinting at :( I know the unit cell is the smallest repetitive unit. But what does have to do with the degrees of freedom? Maybe you can point to a drawing which shows what you are hinting at.
I am thinking if there is two atoms per unit cell they can oscillate relative to each other, which is a degree of freedom which is not there if there is only one atom per unit cell? But then why can't an atom just move relative to another atom in the neighbouring unit cell?
 
It can. You still can have an acoustic mode, but not the optic one(s).
 
why can't u have an optic mode, i.e. neighbouring atoms oscillating in opposite phase wrt each other?
 
aaaa202 said:
I know the unit cell is the smallest repetitive unit. But what does have to do with the degrees of freedom?

A perfect crystal contains a vast number of unit cells - think Avogadro's number for its gram molecular weight - and when you apply an impulse to the crystal, the rigidity of the system makes it felt everywhere.

If one unit cell responds with a particular motion, why should its immediate neighbors respond in some other way? Being identical means that they should have the same response ... they are physically the same.

The the degrees of freedom of the unit cell tell you what responses are possible.

This should be clear from a careful reading of an introductory text like Kittel.
 
aaaa202 said:
why can't u have an optic mode, i.e. neighbouring atoms oscillating in opposite phase wrt each other?

optical modes require atoms to be vibrating out of phase with each other along with different masses/charges to result in optical modes in a crystal.
 
Assume a crystal with one atom per primitive cell. It has only acoustic modes. The wavelength of the phonon determines the phase difference between atoms in the neighbouring cells. If the wavelength is twice the lattice parameter, the neighbours move out of phase. See animated picture of http://en.wikipedia.org/wiki/Phonon.

ehild
 
okay I think I get it. But why is it then that the energy of the optical phonons is much greater than the energy of the acoustical ones?
 
  • #10
You can consider the optical modes as internal vibrations of the molecules forming the basic unit in the primitive cell. The force constants between the atoms of a molecule are usually considerably stronger than the intermolecular forces. At the Brillouin zone boundary, however, the gap between the acoustic and optical mode frequencies/energies can be quite narrow sometimes.

ehild
 

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