A Optical response of In_xGa_1-xAs pin detector

  • A
  • Thread starter Thread starter ribella
  • Start date Start date
  • Tags Tags
    Photocurrent
ribella
Messages
6
Reaction score
0
TL;DR Summary
Plot of the photocurrent versus the wavelength of light of a GaAs/InGaAs/Si top-illuminated pin photodetector
Greetings,

I am trying to obtain a plot of the photocurrent versus the wavelength of light of a GaAs/InGaAs/Si top-illuminated pin photodetector, where the doping ratio for p-type GaAs is conc=1e17, for i-layer In_xGa_1-xAs conc=1e14 and for n-type Si conc=1e18. Firstly, for x=0.05, if we illuminate this structure with top light, the plot of the photocurrent versus the wavelength of light we obtain is as follows:
1726818041237.png


For x=0.1:

1726818141092.png


For x=0.2:

1726818158378.png


Finally, for x=0.3:

1726818194029.png


What I don't fully understand here is that the In_xGa_1-xAs layer is the active layer here and Eg=1.351 eV for x=0.05, so I would expect a peak of around 0.918 micrometres in the wavelength plot of the current coming out of the pin detector. The same situation is Eg=1.279 eV for x=0.1 and the corresponding cut-off wavelength is a peak at 0.970 micrometres. Moreover, for x=0.2 and 0.3 the peak disappears as you can see in the graphs. What could be the physical explanation for these phenomena?
 

Attachments

  • 1726818105394.png
    1726818105394.png
    13.7 KB · Views: 56
Hi. I have got question as in title. How can idea of instantaneous dipole moment for atoms like, for example hydrogen be consistent with idea of orbitals? At my level of knowledge London dispersion forces are derived taking into account Bohr model of atom. But we know today that this model is not correct. If it would be correct I understand that at each time electron is at some point at radius at some angle and there is dipole moment at this time from nucleus to electron at orbit. But how...
Back
Top