Optics - Focal length question

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SUMMARY

The discussion focuses on determining the smallest distance between an object and its real image for a lens with a focal length \( f \). The key equation used is the lens formula \( \frac{1}{s} + \frac{1}{s'} = \frac{1}{f} \). The solution reveals that the total distance \( D \) between the object and image can be expressed as \( D(s) = s + s' \), leading to the conclusion that the minimum distance occurs at \( D = 4f \) when differentiating \( D \) with respect to \( s \) and setting \( D'(s) = 0 \).

PREREQUISITES
  • Understanding of lens formulas, specifically the thin lens equation.
  • Knowledge of calculus, particularly differentiation and critical points.
  • Familiarity with the concepts of object distance \( s \) and image distance \( s' \).
  • Basic grasp of optics and focal length implications in lens systems.
NEXT STEPS
  • Study the derivation of the thin lens formula in optics.
  • Learn about the significance of focal length in lens design.
  • Explore optimization techniques in calculus, focusing on finding minima and maxima.
  • Investigate real-world applications of lenses in photography and microscopy.
USEFUL FOR

Students studying optics, physics educators, and anyone interested in the mathematical principles behind lens behavior and image formation.

Lux0r
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Homework Statement



For a lens with a focal length f, find the smallest distance possible between the object and its real image.

Homework Equations



1/s + 1/s' = 1/f

The Attempt at a Solution



I tried plugging in different numbers for the solution, but I'm not sure how to reach the solution..

The answer is s + s' = 4f
 
Physics news on Phys.org
What is the distance D between the object and image in terms of s and s'? Find the expression D(s). Differentiate D with respect to s and solve the equation D'(s)=0.
 

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