Optics focal length and optical power Question

crystal1001
Messages
4
Reaction score
2
Homework Statement
What is the focal length and optical power (in diopters) of the lenses used to produce the following pairs of object and image distances?

do = 1.0 m
di = 0.33 m
Relevant Equations
focal length: 1/f = 1/do + 1/di
Power (diopters): 1/fD
1/f = 1/dₒ + 1/dᵢ = 1/1.0 + 1/0.33 = 4.03 m (focal length)

Power: 1/4.03 m or 0.248 (0.25)

*around to the2 decimal points? or leave it as a fraction?

((Did I do this correctly? I am not sure if this is correct and is it okay to be in meters not centimeters?))
Please let me know!
 

Attachments

  • 20191118_221442.jpg
    20191118_221442.jpg
    37.4 KB · Views: 274
  • Like
Likes   Reactions: Delta2
Physics news on Phys.org
Looks Ok to me! o:) on this part. See next post by @ehild. Sorry.

The original numbers were 2 significant figures, so the answer should have the same, which you have. The same goes for the units, you matched what was given. 👍
 
Last edited:
crystal1001 said:
do = 1.0 m
di = 0.33 m
Homework Equations: focal length: 1/f = 1/do + 1/di
Power (diopters): 1/fD

1/f = 1/dₒ + 1/dᵢ = 1/1.0 + 1/0.33 = 4.03 m (focal length)
The focal length is f, not 1/f. 1/f is the power (diopters) if f is measured in meters.
 
  • Like
Likes   Reactions: Tom.G

Similar threads

Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K