[Optics] Questions on the Stokes shift

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SUMMARY

The Stokes shift refers to the difference in wavelength between the maxima of excitation and emission spectra during the same electronic transition. A larger Stokes shift indicates greater energy loss, which can negatively impact energy efficiency. However, it also results in a higher signal-to-noise ratio (SNR), facilitating the identification of fluorescence emissions. Understanding the balance between energy efficiency and SNR is crucial for practical applications in optics and fluorescence detection.

PREREQUISITES
  • Understanding of fluorescence spectroscopy
  • Knowledge of electronic transitions in molecules
  • Familiarity with signal-to-noise ratio (SNR) concepts
  • Basic principles of optical emission and excitation
NEXT STEPS
  • Research the impact of Stokes shift on fluorescence efficiency
  • Explore methods to optimize SNR in fluorescence applications
  • Learn about different materials and their Stokes shifts in fluorescence spectroscopy
  • Investigate practical applications of Stokes shift in imaging techniques
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Researchers in optics, chemists specializing in fluorescence spectroscopy, and professionals involved in imaging technologies will benefit from this discussion.

rinalai
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Homework Statement
Is it better to have a large or small Stokes shift, from a practical point of view?
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Here is my answer to this question:

Stokes shift is the difference in wavelength between positions of the band maxima of the excitation and emission spectra of the same electronic transition.
When Stokes shift is large, it means there is more energy loss, which is not favorable regarding energy efficiency. Thus, it is usually better to have a small Stokes shift.
On the other hand, with a larger Stokes shift, meaning that there is a greater wavelength difference between the excitation and emission light, resulting in a higher signal-to-noise ratio(SNR), which makes it easier to identify the fluorescence emission from the particles we are observing.

Are these statements correct?
Any comments and suggestions will be appreciated.
 
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I have no idea what it means to be "practical". Practical in what sense?

rinalai said:
On the other hand, with a larger Stokes shift, meaning that there is a greater wavelength difference between the excitation and emission light, resulting in a higher signal-to-noise ratio(SNR), which makes it easier to identify the fluorescence emission from the particles we are observing.
Why do you think that larger Stokes shift lead to higher SNR?
 

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