Optics: Total Internal Reflection with Triangular Prisms

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The discussion focuses on determining which configurations of a triangular prism will result in total internal reflection of light. The critical angle calculated is 41.8 degrees, and it is established that for total internal reflection to occur, the angle of incidence must exceed this critical angle. Participants clarify the angles of the prism, confirming they are 60, 59, and 30 degrees. A member concludes that the angle of incidence for one configuration is 30 degrees, which is less than the critical angle, indicating that total internal reflection will not occur in that case. The conversation emphasizes the importance of understanding the geometry of light paths within the prism to analyze reflection outcomes.
everlasting89
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Homework Statement


When the striking ray is held perpendicular to the prism, there are four general configurations possible (in the attachment below). Use the figure on the next page to determine analytically which of these four configurations will result in total internal reflection of the light ray. Show analytical work and try each setup. Sketch the results.

Homework Equations



sin θ = (n1 / n2)(sin 90)
Angles of the prism: 90, 59, and 31 degrees

The Attempt at a Solution



Found the critical angle:
sin θ = (n1 / n2)(sin 90)
sin θ = (1.5/1)(sin 90)
sin θ = (1.5/1)(1)
θ = 41.8 degrees

And I know that for total internal reflection the angle of incidence must be larger than the critical angle. However, I am stuck on what (and how) to do next.

Any help is much appreciated!
 

Attachments

  • TIR Problem.JPG
    TIR Problem.JPG
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Welcome to PF! :smile:

What are the angles of the prism? They must be given.

Draw the rays inside the prism and figure out the angle of incidence when the ray strikes the other side.

ehild
 
Thanks, ehild. The prism is 60, 59, and 30 degrees. How do I determine what the rays inside the prism look like?everlasting89
 
everlasting89 said:
Thanks, ehild. The prism is 60, 59, and 30 degrees. How do I determine what the rays inside the prism look like?


everlasting89

You mean 90 instead of 59, I guess :smile:

The ray enters at the first surface at zero angle of incidence (perpendicular to the plane) so it does not change direction in the prism. At what angle with respect to the normal does the ray strike the other surface? It is just simple geometry. I draw one of the configuration. Is the angle of incidence θ smaller of larger than the critical angle of 41.8°?


ehild
 

Attachments

  • totalrrefl.JPG
    totalrrefl.JPG
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Last edited:
Ok, I think I get it. Thanks! So the incidental angle would be 30 degrees which is smaller than the critical angle of 41.8. Thus, it will not result in total internal reflection.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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