Optics: Total Internal Reflection with Triangular Prisms

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Homework Help Overview

The discussion revolves around the analysis of total internal reflection in triangular prisms, specifically focusing on configurations where a light ray strikes the prism at various angles. The problem involves determining which configurations will lead to total internal reflection based on the critical angle derived from the refractive indices of the materials involved.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the angles of the prism and the critical angle necessary for total internal reflection. Questions arise regarding the geometry of the light rays within the prism and how to determine the angle of incidence at the second surface.

Discussion Status

Some participants have provided insights into the geometry of the problem and the implications of the angles involved. There is an ongoing exploration of the relationships between the angles of incidence and the critical angle, with some participants attempting to clarify the conditions for total internal reflection.

Contextual Notes

There is some confusion regarding the angles of the prism, with participants correcting each other on the specific angles involved. The original poster has expressed uncertainty about the next steps in their analysis, indicating a need for further clarification on the setup and calculations.

everlasting89
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Homework Statement


When the striking ray is held perpendicular to the prism, there are four general configurations possible (in the attachment below). Use the figure on the next page to determine analytically which of these four configurations will result in total internal reflection of the light ray. Show analytical work and try each setup. Sketch the results.

Homework Equations



sin θ = (n1 / n2)(sin 90)
Angles of the prism: 90, 59, and 31 degrees

The Attempt at a Solution



Found the critical angle:
sin θ = (n1 / n2)(sin 90)
sin θ = (1.5/1)(sin 90)
sin θ = (1.5/1)(1)
θ = 41.8 degrees

And I know that for total internal reflection the angle of incidence must be larger than the critical angle. However, I am stuck on what (and how) to do next.

Any help is much appreciated!
 

Attachments

  • TIR Problem.JPG
    TIR Problem.JPG
    5.5 KB · Views: 823
Last edited:
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Welcome to PF! :smile:

What are the angles of the prism? They must be given.

Draw the rays inside the prism and figure out the angle of incidence when the ray strikes the other side.

ehild
 
Thanks, ehild. The prism is 60, 59, and 30 degrees. How do I determine what the rays inside the prism look like?everlasting89
 
everlasting89 said:
Thanks, ehild. The prism is 60, 59, and 30 degrees. How do I determine what the rays inside the prism look like?


everlasting89

You mean 90 instead of 59, I guess :smile:

The ray enters at the first surface at zero angle of incidence (perpendicular to the plane) so it does not change direction in the prism. At what angle with respect to the normal does the ray strike the other surface? It is just simple geometry. I draw one of the configuration. Is the angle of incidence θ smaller of larger than the critical angle of 41.8°?


ehild
 

Attachments

  • totalrrefl.JPG
    totalrrefl.JPG
    5 KB · Views: 873
Last edited:
Ok, I think I get it. Thanks! So the incidental angle would be 30 degrees which is smaller than the critical angle of 41.8. Thus, it will not result in total internal reflection.
 

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