Optimal Angle for a Fireman Shooting Water from a 20m High Roof

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SUMMARY

The optimal angle for a fireman to shoot water from a 20m high roof to hit another roof 21m away, while shooting at a speed of 12m/s, requires the use of projectile motion equations. The discussion emphasizes the need to separate the trajectory into horizontal and vertical components, utilizing initial horizontal and vertical velocities, and accounting for gravitational acceleration of -9.8 m/s². By applying kinematic equations to both components, the fireman can determine the precise angle needed for the water to reach the target.

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  • Understanding of projectile motion principles
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  • Basic knowledge of trigonometric functions
  • Ability to resolve vectors into components
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  • Calculate the initial horizontal and vertical velocities using trigonometric functions of the launch angle
  • Explore the application of kinematic equations in projectile motion scenarios
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Physics students, engineers, and anyone interested in understanding projectile motion and its applications in real-world scenarios, such as firefighting techniques.

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A fireman shoots water out of a hose at 12m/s. he is standing on a 20m high roof and is aiming for the top of another roof at the same height, but it is 21 m away. What angle should the fireman aim the hose above the horizontal in order to hit the other roof?

i set up a chart but have no idea what to do now:
x y
vi " '
vf " -'
a 0 -9.8
d 21 0
t
 
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You need to split up the trajectory into horizontal and vertical components, start by writing down the following;

  • Initial Horizontal Velocity*
  • Initial Vertical Velocity*
  • Change in Vertical Displacement
  • Change in Horizontal Displacement
  • Acceleration in the vertical plane

Note that (*) will be trigonometric functions of the launch angle. Once you have done this, apply kinematic equations to each component independently.
 
In questions about projectiles, it is quite often, like in this case that you will need to find the time by resolving it vertically.
 

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